Question
3 and -10
✓
Answer
Let $\alpha=3$ and $\beta=-10$
$\therefore \alpha+\beta=3-10=-7 \text { and } \alpha \beta=3 \times-10=-30$
$\therefore$ and quadratic equation is, $x ^2-(\alpha+\beta) x +\alpha \beta=0$
$\therefore x ^2-(-7) x +(-30)=0$
$\therefore x ^2+7 x -30=0$
$\therefore \alpha+\beta=3-10=-7 \text { and } \alpha \beta=3 \times-10=-30$
$\therefore$ and quadratic equation is, $x ^2-(\alpha+\beta) x +\alpha \beta=0$
$\therefore x ^2-(-7) x +(-30)=0$
$\therefore x ^2+7 x -30=0$
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