3 , ,OD + DA + DB + DC = - Vidyadip

MCQ

$3\,\,\overrightarrow {OD} + \overrightarrow {DA} + \overrightarrow {DB} + \overrightarrow {DC} = $

A
$\overrightarrow {OA} + \overrightarrow {OB} - \overrightarrow {OC} $
B
$\overrightarrow {OA} + \overrightarrow {OB} - \overrightarrow {BD} $
✓
$\overrightarrow {OA} + \overrightarrow {OB} + \overrightarrow {OC} $
D
None of these

✓

Answer

Correct option: C.

$\overrightarrow {OA} + \overrightarrow {OB} + \overrightarrow {OC} $

c
(c) $3\overrightarrow {OD} + \overrightarrow {DA} + \overrightarrow {DB} + \overrightarrow {DC} $

$ = \overrightarrow {OD} + \overrightarrow {DA} + \overrightarrow {OD} + \overrightarrow {DB} + \overrightarrow {OD} + \overrightarrow {DC} $$ = \overrightarrow {OA} + \overrightarrow {OB} + \overrightarrow {OC} .$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 10. vector algebra→STD 12 - 10. vector algebra — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

Let $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1(a>b)$ be a given ellipse length of whose latus rectum is $10 .$ If its eccentricity is the maximum value of the function, $\phi( t )=\frac{5}{12}+ t - t ^{2},$ then $a ^{2}+ b ^{2}$ is equal to

If the matrices has 13 elements , then the possible dimension (order) it can have are:

Choose the correct answer from the given four options.
The probability distribution of a discrete random variable X is given below:

$\text{X}$	$2$	$3$	$4$	$5$
$\text{P}(\text{X})$	$\frac{5}{\text{k}}$	$\frac{7}{\text{k}}$	$\frac{9}{\text{k}}$	$\frac{11}{\text{k}}$

The value of k is:

If the system of equations $x - ky - z = 0$, $kx - y - z = 0$ and $x + y - z = 0$ has a non zero solution, then the possible value of k are

Consider the differential equation $\frac{{dy}}{{dx}} = \frac{{{y^3}}}{{2(x{y^2} - {x^2})}}$

Statement $-1:$ The substitution $z = y^2$ transforms the above equation into a first order homogenous differential equation.

Statement $-2:$ The solution of this differential equation is ${y^2}{e^{ - {y^2}/x}} = C$.

Let $f: R \rightarrow R$ be a function such that $f(x+y)=f(x)+f(y), \quad \forall x, y \in R .$ If $f(x)$ is differentiable at $x=0$, then

$(A)$ $f(x)$ is differentiable only in a finite interval containing zero

$(B)$ $f(x)$ is continuous $\forall x \in R$

$(C)$ $f^{\prime}(x)$ is constant $\forall x \in R$

$(D)$ $f(x)$ is differentiable except at finitely many points

If $y = {\tan ^{ - 1}}\sqrt {{{1 + \cos x} \over {1 - \cos x}}} $, then ${{dy} \over {dx}}$ is equal to

The area between the parabola ${y^2} = 4ax$ and ${x^2} = 8ay$ is

The differential equation which respresents the famliy of curves $\text{y}=\text{e}^{\text{Cx}}$ is :

The corner points of the bounded feasible region are $(60,0),(120,0),(60,40),(40,20)$ and $(20,30)$. For the objective function $z=5 x+10 y \ldots$

$(i)$ Maximum value of $z$.

$(ii)$ Minimum value of $z$.

$(iii)$ Maximum value of $z$ has at

$(iv)$ Minimum value of $z$ has at