Question
$[(-32) ÷ 8 ] ÷ 2 = -32 ÷ [ 8 ÷ 2]$
✓
Answer
$\because\text{LHS}=[(-32)\div8]\div2$
$= \bigg[\frac{-32}{8}\bigg]+2=-4+2=-2$
$\text{and}\ \text{RHS}=(-32)\div[8\div2]$
$\bigg[\frac{-32}{8}\bigg]+2=-4+2=-2$
$\text{and}\ \text{RHS}=(-32)\div[8\div2]$
$=(-32)\div\bigg[\frac{8}{2}\bigg]$
$=(-32)\div4=\frac{(-32)}{4}=-8$
Hence, $LHS \neq RHS.$
$= \bigg[\frac{-32}{8}\bigg]+2=-4+2=-2$
$\text{and}\ \text{RHS}=(-32)\div[8\div2]$
$\bigg[\frac{-32}{8}\bigg]+2=-4+2=-2$
$\text{and}\ \text{RHS}=(-32)\div[8\div2]$
$=(-32)\div\bigg[\frac{8}{2}\bigg]$
$=(-32)\div4=\frac{(-32)}{4}=-8$
Hence, $LHS \neq RHS.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write the coefficient of $2$ in the following:
$-\frac32\text{ax}^2+\text{yx}$
→$-\frac32\text{ax}^2+\text{yx}$
Find the product:
$4.74 \times 10$
→$4.74 \times 10$
Divide:
148 by 0.074
148 by 0.074
Find the value of:
$11^2$
→$11^2$
Simplify and write in exponential form.
$a^3 \times a^2 \times a^7$
→$a^3 \times a^2 \times a^7$
Evaluate:
(0.04)2
(0.04)2
Draw all lines of symmetry for the following figure.
State the number of lines of symmetry for figure: A rhombus
Fill in the blank: $\Big(\frac{-65}{14}\Big)+(\dots)=2\frac{1}{2}$
→Find the value of:
70
70