MCQ
$3.4\, gm\, H_2O_2$ is present in its $112\, ml$ solution. Volume strength of this solution is ....... $V$.
- A$0.224$
- B$20$
- C$5$
- ✓$10$
For $\mathrm{H}_{2} \mathrm{O}_{2} ; \mathrm{M}=\frac{\text { Volume strength }}{11.2}$
$\frac{1}{10^{-3} \times 1120}=\frac{\text { Volume strength }}{11.2}$
Volume strength $=10$
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$(i)$ $PCl_3 + 3H_2O \to H_3PO_3 + 3HCl$
$(ii)$ $SF_4 + 3H_2O \to H_3SO_3 + 4HF$
$(iii)$ $BCI_3 + 3H_2O \to H_3BO_3 + 3HCl$
$(IV)$ $XeF_6 + 3H_2O \to XeO_3 + 6HF$
Then according to given information the incorrect statement is
