MCQ
$3.4\, gm\, H_2O_2$ is present in its $112\, ml$ solution. Volume strength of this solution is ....... $V$.
- A$0.224$
- B$20$
- C$5$
- ✓$10$
✓
Answer
Correct option: D.
$10$
d
Molarity of $\mathrm{H}_{2} \mathrm{O}_{2}$ solution $=\frac{\frac{3.4}{34}}{112 \times 10^{-3}}$
Molarity of $\mathrm{H}_{2} \mathrm{O}_{2}$ solution $=\frac{\frac{3.4}{34}}{112 \times 10^{-3}}$
For $\mathrm{H}_{2} \mathrm{O}_{2} ; \mathrm{M}=\frac{\text { Volume strength }}{11.2}$
$\frac{1}{10^{-3} \times 1120}=\frac{\text { Volume strength }}{11.2}$
Volume strength $=10$
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