Question
$\frac{3}{4}(\text{x}-1)=\text{x}-3$

Answer

$\frac{3}{4}(\text{x}-1)=\text{x}-3$
On expanding the brackets on both sides, we get
$=\frac{\text{3x}}{4}-\frac34=\text{x}-3$
Transposing $\frac34\text{x}$ to R.H.S. and 3 to L.H.S., we get
$\Rightarrow3-\frac34=\text{x}-\frac34\text{x}$
$\Rightarrow\frac{12-3}{4}=\frac{4\text{x}-3\text{x}}{4}$
$\Rightarrow\frac{9}{4}-=\frac{\text{x}}{4}$
Multiplying both sides by 4, we get
$\Rightarrow\text{x}=9$
Verification:
Substituting x = 9 on both sides, we get
$\frac{3}{4}(9-1)=9-3$
$\frac34\times8=6$
L.H.S. = R.H.S.
Hence, verified.

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