(3+6+12+ +1536)=? - Vidyadip

MCQ

$(3+6+12+\ldots+1536)=?$

A
1023
B
3069
C
2046
D
4092

✓

Answer

(b) 3069
Explanation: This is a GP in which $a =3, r =\frac{6}{3}=2$ and $l =1536$
$\therefore$ required sum $=\frac{(l r-a)}{(r-1)}=\frac{(1536 \times 2-3)}{(2-1)}=(3072-3)=3069$.

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