Question
$\frac{-3}{7}\div\big(\frac{-7}{3}\big)=$ _______.
✓
Answer
$\frac{-3}{7}\div\big(\frac{-7}{3}\big)=\frac{9}{49}.$ Solution: $\because$ Reciprocal of $\frac{-7}{3}$ is $\frac{3}{-7}.$ $\therefore\frac{-3}{7}+\big(\frac{3}{-7}\big)$ Product of rational numbers, $=\frac{\text{Product of numerators}}{\text{Product of denominators}}$ $=\frac{(-3\times3)}{7\times(-7)}=\frac{-9}{-49}=\frac{9}{49}$ Hence, $\frac{-3}{7}\div\big(\frac{-7}{3}\big)=\frac{9}{49}.$
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