39x^3 (50x^2 - 98) 26x^2 (5x + 7) - Vidyadip

MCQ

$39x^3 (50x^2 - 98) \div 26x^2 (5x + 7)$

A
$3x(5x + 7)$
B
$3x$
C
$5x - 7$
✓
$3x(5x - 7)$

✓

Answer

Correct option: D.

$3x(5x - 7)$

D. $3x(5x - 7)$
Solution:
$\frac{39\text{x}^3(50\text{x}^2-98)}{26\text{x}^2(5\text{x}+7)}$
$\Rightarrow\frac{13\times3\text{x}^3\times2(25\text{x}^2-49)}{13\times2\text{x}^2(5\text{x}+7)}$
$\Rightarrow\frac{13\times3\text{x}^2\times2((5\text{x})^2-(7)^2)}{13\times2\text{x}^2\times(5\text{x}+7)}$
$\Rightarrow\frac{13\times3\text{x}^2\times2(5\text{x}+7)(5\text{x}-7)}{2\times13\text{x}^2(5\text{x}+7)}$
Cancel the common factors
$\Rightarrow3\text{x}(5\text{x}-7)$

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