Question
$\frac{3\text{t}-2}{3}+\frac{2\text{t}+3}{2}=\text{t}+\frac{7}{6}$

Answer

Given, $\frac{3\text{t}-2}{3}+\frac{2\text{t}+3}{2}=\text{t}+\frac{7}{6}$ $\frac{2(3\text{t}-2)+3(2\text{t}+3)}{6}=\frac{6\text{t}+7}{6} 6t - 4 + 6t + 9 = 6t + 7$
$12t + 5 = 6t + 7$
$12t - 6t = 7 - 5$
$6t = 2$
$\frac{6\text{t}}{6}=\frac{2}{6}$ $\text{t}=\frac{1}{3}$

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