MCQ
$3x + 10 = 0$ will have:
- ✓Unique solution
- BTwo solutions
- CInfinitely many solutions
- DNo solutions
✓
Answer
Correct option: A.
Unique solution
$3\text{x}+10 = 0$
$\text{x}=\frac{-10}{3}.$
Hence, only one solution is possible.
$\text{x}=\frac{-10}{3}.$
Hence, only one solution is possible.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$ABCD$ is a rhombus such that $\angle\text{ACB}=50^{\circ}.$ Then, $\angle\text{ADB}=?$
→In figure, $ABCD$ is a quadrilateral in which $AB = BC$ and $AD = DC$. The measure of $\angle\text{BCD}$ is:
→$(x + 1)$ is a factor of $x^n +1 $ only if.
→In the given figure, $AB ||\ || CD$ and $O$ is the centre of the circle. If $\angle\text{ADC}=25^\circ,$ then the measure of $\angle\text{AEB}$ is:
→In a figure, if $OP \| RS$, $\angle\text{OPQ}=110^\circ$ and $\angle\text{QRS}=130^\circ,$ then $\angle\text{PQR}$ is equal to: 
→An ice cream cone has hemispherical top. If the height of the cone is $9\ cm$ and base radius is $2.5\ cm,$ then the volume of ice cream is:
→If the base radius of a cone is doubled and its height is halved, then which of the following is true regarding its volume?
In Fig. O is the centre of the circle such that $\angle A O C=130^{\circ}$, then $\angle A B C=$
→Express $y$ in terms of $x$ in the equation $5x - 2y = 7.$
→$PS$ and $RS$ are two chord's of a circle such that $PQ = 10\ cm$ and $RS = 24\ cm$ and $PQ || RS.$ The distance between $PQ$ and $RS$ is $17\ cm. $ Find the radius of circle.
→