Question
$3x - 2(2x - 5) = 2(x + 3) - 8$
✓
Answer
$3x - 2(2x - 5) = 2(x + 3) - 8$
On expanding the brackets on both sides, we get
$= 3x - 2 × 2x + 2 × 5 = 2 × x + 2 × 3 - 8$
$= 3x - 4x + 10 = 2x + 6 - 8$
$= -x + 10 = 2x - 2$
Transposing $x$ to $R.H.S$. and $2$ to $L.H.S.$, we get
$= 10 + 2 = 2x + x$
$= 3x = 12$
Dividing both sides by $3$, we get
$=\frac{3\text{x}}{3}=\frac{12}{3}$
$=\text{x}=4$
Verification:
Substituting $x = 4$ on both sides, we get
$3(4) - 2{2(4) - 5} = 2(4 + 3) - 8$
$12 - 2(8 - 5) = 14 - 8$
$12 - 6 = 6$
$6 = 6$
$L.H.S. = R.H.S.$
Hence, verified.
On expanding the brackets on both sides, we get
$= 3x - 2 × 2x + 2 × 5 = 2 × x + 2 × 3 - 8$
$= 3x - 4x + 10 = 2x + 6 - 8$
$= -x + 10 = 2x - 2$
Transposing $x$ to $R.H.S$. and $2$ to $L.H.S.$, we get
$= 10 + 2 = 2x + x$
$= 3x = 12$
Dividing both sides by $3$, we get
$=\frac{3\text{x}}{3}=\frac{12}{3}$
$=\text{x}=4$
Verification:
Substituting $x = 4$ on both sides, we get
$3(4) - 2{2(4) - 5} = 2(4 + 3) - 8$
$12 - 2(8 - 5) = 14 - 8$
$12 - 6 = 6$
$6 = 6$
$L.H.S. = R.H.S.$
Hence, verified.
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