Question
3x - 2(2x - 5) = 2(x + 3) - 8
✓
Answer
3x - 2(2x - 5) = 2(x + 3) - 8
On expanding the brackets on both sides, we get
= 3x - 2 × 2x + 2 × 5 = 2 × x + 2 × 3 - 8
= 3x - 4x + 10 = 2x + 6 - 8
= -x + 10 = 2x - 2
Transposing x to R.H.S. and 2 to L.H.S., we get
= 10 + 2 = 2x + x
= 3x = 12
Dividing both sides by 3, we get
$=\frac{3\text{x}}{3}=\frac{12}{3}$
$=\text{x}=4$
Verification:
Substituting x = 4 on both sides, we get
3(4) - 2{2(4) - 5} = 2(4 + 3) - 8
12 - 2(8 - 5) = 14 - 8
12 - 6 = 6
6 = 6
L.H.S. = R.H.S.
Hence, verified.
On expanding the brackets on both sides, we get
= 3x - 2 × 2x + 2 × 5 = 2 × x + 2 × 3 - 8
= 3x - 4x + 10 = 2x + 6 - 8
= -x + 10 = 2x - 2
Transposing x to R.H.S. and 2 to L.H.S., we get
= 10 + 2 = 2x + x
= 3x = 12
Dividing both sides by 3, we get
$=\frac{3\text{x}}{3}=\frac{12}{3}$
$=\text{x}=4$
Verification:
Substituting x = 4 on both sides, we get
3(4) - 2{2(4) - 5} = 2(4 + 3) - 8
12 - 2(8 - 5) = 14 - 8
12 - 6 = 6
6 = 6
L.H.S. = R.H.S.
Hence, verified.
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