MCQ
${{3{x^2} + 5} \over {{{({x^2} + 1)}^2}}} = {a \over {{x^2} + 1}} + {b \over {{{({x^2} + 1)}^2}}}$, then $(a,b) = $
  • A
    $(2, 3)$
  • $(3, 2)$
  • C
    $(-2,3)$
  • D
    $(-3, 2)$

Answer

Correct option: B.
$(3, 2)$
b
(b) $3{x^2} + 5 = a\,({x^2} + 1) + b$

$ \Rightarrow $ $a = 3,\,a + b = 5 \Rightarrow b = 2$;

$\therefore (a,\,b) = (3,\,2)$.

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