MCQ
${{3{x^2} + 5} \over {{{({x^2} + 1)}^2}}} = {a \over {{x^2} + 1}} + {b \over {{{({x^2} + 1)}^2}}}$, then $(a,b) = $
- A$(2, 3)$
- ✓$(3, 2)$
- C$(-2,3)$
- D$(-3, 2)$
$ \Rightarrow $ $a = 3,\,a + b = 5 \Rightarrow b = 2$;
$\therefore (a,\,b) = (3,\,2)$.
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