MCQ
${4 \over {1 + \sqrt 2 - \sqrt 3 }} = $
- ✓$2 + \sqrt 2 + \sqrt 6 $
- B$1 + \sqrt 2 + \sqrt 3 $
- C$3 + \sqrt 2 + \sqrt 3 $
- DNone of these
$ = {{4(1 + \sqrt 2 + \sqrt 3 )} \over {3 + 2\sqrt 2 - 3}} + {{\sqrt 6 (\sqrt 3 - \sqrt 2 )} \over {3 - 2}}$
$ = \sqrt 2 (1 + \sqrt 2 + \sqrt 3 ) = 2 + \sqrt 2 + \sqrt 6 $.
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$(A)$ $Z \cup T_1 \cup T_2 \subset S$
$(B)$ $T_1 \cap\left(0, \frac{1}{2024}\right)=\phi$, where $\phi$ denotes the empty set
$(C)$ $T_2 \cap(2024, \infty) \neq \phi$
$(D)$ For any given $a, b \in Z , \cos (\pi(a+b \sqrt{2}))+i \sin (\pi(a+b \sqrt{2})) \in Z$ if and only if $b=0$, where $i=\sqrt{-1}$