Question
$4^0+5^0+6^0=(4+5+6)^0$
✓
Answer
False.
Solution:
$\text { Here, } 4^0+5^0+6^0$
$=1+1+1$
$=3\left[\therefore a^0=1\right]$
$\text { and }(4+5+6)^0$
$=(15)^0$
$=1$
$\text { Hence, } 4^0+5^0+6^0$
$\neq(4+5+6)^0$
Solution:
$\text { Here, } 4^0+5^0+6^0$
$=1+1+1$
$=3\left[\therefore a^0=1\right]$
$\text { and }(4+5+6)^0$
$=(15)^0$
$=1$
$\text { Hence, } 4^0+5^0+6^0$
$\neq(4+5+6)^0$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find: 8$\div \frac{7}{3}$
→Find: $\frac{2}{5} \div \frac{1}{2}$
→All parallelograms having equal areas have same perimeters. Observe all the four triangles $FAB, EAB, DAB$ and $CAB$ as shown in Fig. :
All triangles have the same base and the same altitude.
→All triangles have the same base and the same altitude.
Rhombus is a figure that has ______ lines of symmetry and has a rotational symmetry of order _______.
Which of the following statements are true and which of them are false?
If two sides and one angle of a triangle are equal to the corresponding two sides and angle of another triangle, the triangles are congruent.
If two sides and one angle of a triangle are equal to the corresponding two sides and angle of another triangle, the triangles are congruent.
Find
$37.8 \div 1.4$
→$37.8 \div 1.4$
Classify into monomials, binomials and trinomials: $7\ mn$
→Classify into monomials, binomials and trinomials: $1+x+x^2$
→Simplify and write in exponential form.
$2^5 \times 2^3$
→$2^5 \times 2^3$
In the figure of a cube.
Which faces intersect at edge $FB?$
→Which faces intersect at edge $FB?$