MCQ
$-\frac{4}{3}\text{y}=-\frac{3}{4}$, then $y = ?$
- A$-\Big(\frac{3}{4}\Big)^2$
- B$-\Big(\frac{4}{3}\Big)^2$
- ✓$\Big(\frac{3}{4}\Big)^2$
- D$\Big(\frac{4}{3}\Big)^2$
Given, $-\frac{4}{3}\text{y}=-\frac{3}{4}$
$\text{y}=-\frac{3}{4}\times-\frac{3}{4}$
$\text{y}=\Big(\frac{3}{4}\Big)^2$
Hence, the value of $y$ is $\Big(\frac{3}{4}\Big)^2.$
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