Question
✓
Answer
: In $\triangle X Y Z$ and $\triangle L M N$,
$\begin{array}{l}
\angle Y =100^{\circ}, \angle M =100^{\circ}, \therefore \angle Y \cong \angle M \\
\angle Z =30^{\circ}, \angle N =30^{\circ}, \therefore \angle Z \cong \angle N \\
\therefore \triangle XYZ \sim \triangle LMN \quad \ldots \ldots \text { by AA test. }
\end{array}$
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