Question
$\frac45-\text{x}=\frac35$
✓
Answer
$\frac45-\text{x}=\frac35$
Subtracting $\frac45$ from both sides,
we get $\frac{4}{5}-\text{x}-\frac45=\frac35-\frac45$
$-\text{x}=\frac35-\frac45$
$-\text{x}=-\frac15$
Dividing both sides by $-1,$
we get $-\text{x}\times(-1)=-\frac15\times(-1)$
$\text{x}=\frac15$
Verification: Substituting $\text{x}=\frac15$ in
$L.H.S$., we get $\text{L.H.S.}=\frac{4}{5}-\frac15=\frac{4-1}{5}=\frac35,$ and $\text{R.H.S.} = \frac35$
$L.H.S. = R.H.S$. Hence, verified.
Subtracting $\frac45$ from both sides,
we get $\frac{4}{5}-\text{x}-\frac45=\frac35-\frac45$
$-\text{x}=\frac35-\frac45$
$-\text{x}=-\frac15$
Dividing both sides by $-1,$
we get $-\text{x}\times(-1)=-\frac15\times(-1)$
$\text{x}=\frac15$
Verification: Substituting $\text{x}=\frac15$ in
$L.H.S$., we get $\text{L.H.S.}=\frac{4}{5}-\frac15=\frac{4-1}{5}=\frac35,$ and $\text{R.H.S.} = \frac35$
$L.H.S. = R.H.S$. Hence, verified.
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