Question
$4^9$ is greater than $16^3$
✓
Answer
True.
Solution:
$\therefore 16^3=\left(4^2\right)^3$
${\left[\therefore 16=4 \times 4=4^2\right]}$
$=4^6$
Now, in $4^9$ and $4^6, 4^9>4^6$ as powers $9>6$
Solution:
$\therefore 16^3=\left(4^2\right)^3$
${\left[\therefore 16=4 \times 4=4^2\right]}$
$=4^6$
Now, in $4^9$ and $4^6, 4^9>4^6$ as powers $9>6$
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