MCQ
$4d, 5 \mathrm{p}, 5 \mathrm{f}$ and $6 \mathrm{p}$ orbitals are arranged in the order of decreasing energy. The correct option is
  • $5 f>6 p>5 p>4 d$
  • B
    $6 p>5 f>5 p>4 d$
  • C
    $6 p>5 f>4 d>5 p$
  • D
    $5 f>6 p>4 d>5 p$

Answer

Correct option: A.
$5 f>6 p>5 p>4 d$
a
According to $(n+l)$ rule, correct order of energy is $5 f>6 \mathrm{p}>5 \mathrm{p}>4 \mathrm{d}$

For same value of $(n+l) ;$ higher is the value of $n$, higher will be the energy.

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