Question
$(-5)^{-2} \times(-5)^{-3}=(-5)^{-6}$
✓
Answer
False.
Solution:
$LHS =(-5)^{-2} \times(-5)^{-3}$
Using law of exponents, $a^m \times a^n=(a)^{m+n}$ [$\because$ a is non-zero integer]
$\therefore(-5)^{-2} \times(-5)^{-3}=(-5)^{-2-3}=(-5)^{-5}$
$LHS ≠ RHS$
Solution:
$LHS =(-5)^{-2} \times(-5)^{-3}$
Using law of exponents, $a^m \times a^n=(a)^{m+n}$ [$\because$ a is non-zero integer]
$\therefore(-5)^{-2} \times(-5)^{-3}=(-5)^{-2-3}=(-5)^{-5}$
$LHS ≠ RHS$
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