Question
50 mL KOH solution neutralise completely 5 mL HNO3 solution. What volume of HNO3 is required for complete neutrisation of 15 mL of KOH solution?

Answer

50 mL KOH solution neutralise 5 mL $HNO _3$ solution
$\therefore 15 \text {mL}~ \text {KOH}$ solution will neutralise, $\frac{15 \times 5}{50}=1.5 \text {mL} \quad \text {HNO} _3$ solution.

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