Question
$\frac{5(1-\text{x})+3(1+\text{x})}{1-2\text{x}}=8$

Answer

Given, $\frac{5(1-\text{x})+3(1+\text{x})}{1-2\text{x}}=8 5(1 - x) + 3(1 + x) = 8(1 - 2x)$
$5 - 5x + 3 + 3x = 8 - 16x$
$8 - 2x = 8 - 16x$
$16x - 2x = 8 - 8$
$14x = 0$
$\frac{14\text{x}}{14}=\frac{0}{14}$
$x = 0$

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