MCQ
$5\frac{1}{6}\div\frac{9}{2}$ is equal to:
- A$\frac{31}{6}$
- B$\frac{1}{27}$
- C$5\frac{1}{27}$
- ✓$\frac{27}{31}$
✓
Answer
Correct option: D.
$\frac{27}{31}$
Given, $5\frac{1}{6}+\frac{9}{2}$
$\because5\frac{1}{6}=\frac{(5\times6)+1}{6}=\frac{30+1}{6}=\frac{31}{6}$
$\big[\because$ reciprocal of $\frac{9}{2}=\frac{2}{9}\big]$
$\therefore5\frac{1}{6}+\frac{9}{2}=\frac{31}{6}\times\frac{2}{9}=\frac{31}{27}$
$\because5\frac{1}{6}=\frac{(5\times6)+1}{6}=\frac{30+1}{6}=\frac{31}{6}$
$\big[\because$ reciprocal of $\frac{9}{2}=\frac{2}{9}\big]$
$\therefore5\frac{1}{6}+\frac{9}{2}=\frac{31}{6}\times\frac{2}{9}=\frac{31}{27}$
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