MCQ
$(64)^\frac{-2}{3}\times\Big(\frac{1}{4}\Big)^{-3}$ equals to
  • $4$
  • B
    $\frac{1}{4}$
  • C
    $1$
  • D
    $16$

Answer

Correct option: A.
$4$

$(64)^\frac{-2}{3}\times\Big(\frac{1}{4}\Big)^{-3}$
$=(4^3)^{-\frac{2}{3}}\times\Big(\frac{1}{4}\Big)^{-3}$
$\Rightarrow4^{-2}\times\frac{1}{4^{-3}}$
$\Rightarrow4^{-2+3}=4^1=4$

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