Question
$(6+\sqrt{27})-(3+\sqrt{3})+(1-2\sqrt{3})$ when simplified is:

Answer

  1. Positive and rational.
    Solution:
    $(6+\sqrt{27})-(3+\sqrt{3})+(1-2\sqrt{3})$
    $=6+3\sqrt{3}-3-\sqrt{3}+1-2\sqrt{3}$
    $=6+1-3$
    $=4$
    Positive and rational.

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