Question
$2 m^2-5 m=0, m=2, \frac{5}{2}$

Answer

$2 m^2-5 m=0 $
$\text { Put } m =2 \Rightarrow 2(2)^2-5 \times 2 \Rightarrow 2 \times 4-10 \Rightarrow 8-10 \Rightarrow-2 $
$\text { Put } m =\frac{5}{2} \Rightarrow 2\left(\frac{5}{2}\right)^2-5 \times \frac{5}{2} \Rightarrow 2 \times \frac{25}{4}-\frac{25}{2} \Rightarrow \frac{25}{2}-\frac{25}{2}=0$
$\therefore m =2$ is not root of the equation and $m =\frac{5}{2}$ is a root of the equation.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free