Question
$(-8) + (-8) + (-8) = \_\_\_\_\_ \times (-8)$
✓
Answer
Let $x$ be the missing number.
Then, $-8 - 8 - 8 = x \times (-8)$
$\Rightarrow-24=\text{x}\times(-8)$
$\Rightarrow\frac{-24}{-8}=\text{x}$
$\Rightarrow\text{x}=3$
Hence, $(-8) + (-8) + (-8) = 3 \times (-8)$
Then, $-8 - 8 - 8 = x \times (-8)$
$\Rightarrow-24=\text{x}\times(-8)$
$\Rightarrow\frac{-24}{-8}=\text{x}$
$\Rightarrow\text{x}=3$
Hence, $(-8) + (-8) + (-8) = 3 \times (-8)$
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