Question
$\frac{8}{18}-\frac{8}{15}=\frac{8}{3}$
✓
Answer
We have, $\frac{8}{18}-\frac{8}{15} LCM$ of $18$ and $15.$
$\begin{array}{c|c}2&18,15\\\hline3&9,15\\\hline3&3,5\\\hline5&1,5\\\hline&1,1\end{array}$
$\therefore LCM$ of $18$ and $15 = 2 \times 3 \times 3 \times 5 = 90.$
Now, converting the given fractions to equivalent fraction with denominator $90.$
$\frac{8\times5}{18\times5}=\frac{40}{90}$ and $\frac{8\times6}{15\times6}=\frac{48}{90}$
$\therefore\frac{40}{90}\frac{4}{7}$
$\begin{array}{c|c}2&18,15\\\hline3&9,15\\\hline3&3,5\\\hline5&1,5\\\hline&1,1\end{array}$
$\therefore LCM$ of $18$ and $15 = 2 \times 3 \times 3 \times 5 = 90.$
Now, converting the given fractions to equivalent fraction with denominator $90.$
$\frac{8\times5}{18\times5}=\frac{40}{90}$ and $\frac{8\times6}{15\times6}=\frac{48}{90}$
$\therefore\frac{40}{90}\frac{4}{7}$
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