Question
8.8g carbon dioxide
✓
Answer
Given : Mass of Carbon dioxide $\left( CO _2\right) m =8.8 g$.
To find : Number of molecules in 8.8 g of carbon dioxide.
Solution : Molecular mass of $\left( CO _2\right) M =$ (Atomic mass of C) $\times 1+$ (Atomic mass of O $) \times 2$
$\therefore$ Molecular mass of $\left( CO _2\right) M =12 \times 1+16 \times 2=12+32$
Molecular mass of $\left( CO _2\right) M =44$
According to the formula, Number of moles in the given $CO _2( n )$
$\therefore 1 mol$ of $CO _2$ contains $6.022 \times 10^{23}$ molecules.
$\therefore 0.2 mol$ of $CO _2$ contains $0.2 \times 6.022 \times 10^{23}$ molecules.
$=1.2044 \times 10^{23} \text { molecules }$
that is $8.8 g_{ g } CO _2$ contains $1.2044 \times 10^{23}$ molecules of $CO _2$.
8.8 g of $CO _2$ contains $1.2044 \times 10^{23}$ molecules of $CO _2$.
To find : Number of molecules in 8.8 g of carbon dioxide.
Solution : Molecular mass of $\left( CO _2\right) M =$ (Atomic mass of C) $\times 1+$ (Atomic mass of O $) \times 2$
$\therefore$ Molecular mass of $\left( CO _2\right) M =12 \times 1+16 \times 2=12+32$
Molecular mass of $\left( CO _2\right) M =44$
According to the formula, Number of moles in the given $CO _2( n )$
$\therefore 1 mol$ of $CO _2$ contains $6.022 \times 10^{23}$ molecules.
$\therefore 0.2 mol$ of $CO _2$ contains $0.2 \times 6.022 \times 10^{23}$ molecules.
$=1.2044 \times 10^{23} \text { molecules }$
that is $8.8 g_{ g } CO _2$ contains $1.2044 \times 10^{23}$ molecules of $CO _2$.
8.8 g of $CO _2$ contains $1.2044 \times 10^{23}$ molecules of $CO _2$.
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→Given:
Mass $( m )=20 kg$
Height $(h)=5 m$
Time $( t )=20 s$
Acceleration due to gravity $( g )=9.8 m / s ^2$
To Find:
Power $( P )=$ ?
Formula:
$P=\frac{\text { mgh }}{t}$