MCQ
$9 \sec ^2 A-9 \tan ^2 A=$
- ✓$9$
- B$1$
- C$0$
- D$99$
✓
Answer
Correct option: A.
$9$
$\text { Explanation: Given: } 9 \sec ^2 A-9 \tan ^2 A$
$=9\left(\sec ^2 A-\tan ^2 A\right)$
$=9 \times 1=9 \ldots\left[\because \sec ^2 \theta-\tan ^2 \theta=1\right]$
$=9\left(\sec ^2 A-\tan ^2 A\right)$
$=9 \times 1=9 \ldots\left[\because \sec ^2 \theta-\tan ^2 \theta=1\right]$
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