Question
$9\frac{1}{4}=\text{y}-1\frac{1}{3}$
✓
Answer
$9\frac{1}{4}=\text{y}-1\frac{1}{3} $
$\Rightarrow\frac{37}{4}$
$=\text{y}-\frac{4}{3}$
$\Rightarrow\frac{37}{4}+\frac{4}{3}$
$=\text{y}-\frac{4}{3}+\frac{4}{3}$ (Adding $\frac{4}{3}$ to both sides)
$\Rightarrow\text{y}=\frac{111+16}{12}$
$=\frac{127}{12}$
$=10\frac{7}{12}$
$\therefore\text{y}=10\frac{7}{12}$ Verification: $\text{R.H.S}$
$=\text{y}-1\frac{1}{3}=10\frac{7}{12}-1\frac{1}{3}$
$=\frac{127}{12}-\frac{4}{3}$
$=\frac{127-16}{12}=\frac{111}{12}=\frac{37}{4}$ (Dividing by $3$)
$=9\frac{1}{4}=\text{L.H.S}$
$\Rightarrow\frac{37}{4}$
$=\text{y}-\frac{4}{3}$
$\Rightarrow\frac{37}{4}+\frac{4}{3}$
$=\text{y}-\frac{4}{3}+\frac{4}{3}$ (Adding $\frac{4}{3}$ to both sides)
$\Rightarrow\text{y}=\frac{111+16}{12}$
$=\frac{127}{12}$
$=10\frac{7}{12}$
$\therefore\text{y}=10\frac{7}{12}$ Verification: $\text{R.H.S}$
$=\text{y}-1\frac{1}{3}=10\frac{7}{12}-1\frac{1}{3}$
$=\frac{127}{12}-\frac{4}{3}$
$=\frac{127-16}{12}=\frac{111}{12}=\frac{37}{4}$ (Dividing by $3$)
$=9\frac{1}{4}=\text{L.H.S}$
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