MCQ
$(-9)^3 \div (-9)^8$ is equal to:
- A$(9)^5$
- B$(9)^{-5}$
- C$(-9)^5$
- ✓$(-9)^{-5}$
✓
Answer
Correct option: D.
$(-9)^{-5}$
Given,
$(-9)^{3} \div (-9)^{8}$
Using law of exponents, $a^m + a^n = (a)^{m-n}[\because$ a is non-zero integer$]$
$\therefore$$(-9)^{3} + (-9)^{8} = (-9)^{3-8}$
$(-9)^{-5}$
$(-9)^{3} \div (-9)^{8}$
Using law of exponents, $a^m + a^n = (a)^{m-n}[\because$ a is non-zero integer$]$
$\therefore$$(-9)^{3} + (-9)^{8} = (-9)^{3-8}$
$(-9)^{-5}$
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