$9.3 \mathrm{~g}$ of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ' $\mathrm{P}$ '. The mass of product ' $\mathrm{P}$ ' obtained is $26.4 \mathrm{~g}$. The percentage yield is ......... $%$.
A$70$
B$80$
C$90$
D$100$
JEE MAIN 2024, Medium
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B$80$
b $93 \mathrm{~g}$ of aniline produces $330 \mathrm{~g}$ of $2,4,6-$ tribromoaniline. Hence $9.3 \mathrm{~g}$ of aniline should produce $33 \mathrm{~g}$ of $2, 4, 6-$tribromoaniline. Hence percentage yield $\frac{26.4 \times 100}{33}=80 \%$
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Ammonolysis of Alkyl halides followed by the treatment with $NaOH$ solution can be used to prepare primary, secondary and tertiary amines. The purpose of $NaOH$ in the reaction is :