Question
$\frac{9}{6}$ lies between $1$ and $2.$

Answer

First, we convert the given rational numbers with denominator as $6,$
we get $1=1\times\frac{6}{6}=\frac{6}{6}$
$2=2\times\frac{6}{6}=\frac{12}{6}$
$\because\frac{6}{6}<\frac{9}{6}<\frac{12}{6}$
$\therefore1<\frac{9}{6}<2$ Therefore, $\frac{9}{6}$ lies between $1$ and $2.$

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