MCQ
$99\%$ of a radioactive element will decay between
  • $6$ and $7$ half lives
  • B
    $7 $ and $8 $ half lives
  • C
    $8$ and $9$ half lives
  • D
    $9$ half lives

Answer

Correct option: A.
$6$ and $7$ half lives
a
(a) $N = {N_0}{\left( {\frac{1}{2}} \right)^n} $

$\Rightarrow \frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n}$

$ \Rightarrow \frac{1}{{100}} = {\left( {\frac{1}{2}} \right)^n}$

$\Rightarrow {2^n} = 100$

$n$ comes out in between $6$ and $7.$

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