MCQ
$9\sec^2\text{A}-9\tan^2\text{A}$ is equal to:
- A$1$
- ✓$9$
- C$8$
- D$0$
✓
Answer
Correct option: B.
$9$
Given,
$9\sec^2\text{A}-9\tan^2\text{A}$
$=9(\sec^2\text{A}-\tan^2\text{A})$
We know that, $\sec^2-\tan^2\text{A}=1$
Therefore, $9\sec^2\text{A}-9\tan^2\text{A}=9$
Hence, the correct option is $(b).$
$9\sec^2\text{A}-9\tan^2\text{A}$
$=9(\sec^2\text{A}-\tan^2\text{A})$
We know that, $\sec^2-\tan^2\text{A}=1$
Therefore, $9\sec^2\text{A}-9\tan^2\text{A}=9$
Hence, the correct option is $(b).$
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