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STD 11 - 13. oscillations — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 13. oscillations4 Marks
MCQ
A $0.10\, kg$ block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: $x = (10\,cm)\cos [(10\,rad/s)\,t + \pi /2\,rad]$. What is the maximum acceleration experienced by the block
  • ✓
    $10\,\,m/{s^2}$
  • B
    $10\,\pi \,m/{s^2}$
  • C
    $\frac{{10\pi }}{2}\,m/{s^2}$
  • D
    $\frac{{10\pi }}{3}\,m/{s^2}$
✓

Answer

Correct option: A.
$10\,\,m/{s^2}$
a
(a) $a = 10 \times {10^{ - 2}}m$ and $\omega = 10\;rad/sec$
${A_{\max }} = {\omega ^2}a = 10 \times {10^{ - 2}} \times {10^2} = 10\;m/{\sec ^2}$

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