Question
A 1 meter thick cement wall can withstand a pressure of $10^5 N / m ^2$. What should be the thickness of the wall at the base of a 200 m depth water of dam?
(Density of water $=10^3 kg / m ^3$ and acceleration due to gravity $=9.8 m / s ^2$ )

Answer

The value of pressure (P) on the wall near the dam
$\begin{array}{l}= h \rho g \\ =200 \times 10^3 \times 9.8 \\ =19.6 \times 10^5 N / m ^2\end{array}$
Since the required thickness of the wall to bear the pressure of $10^5 N / m =1 m$
Required thickness of the wall to withstand a pressure of $19.6 \times 10^5 N / m ^2$
$=\left(\frac{1}{10^5}\right) \times 19.6 \times 10^5=19.6 m$

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