A 100 mark examination was administered to a class of 50 students… - Vidyadip

MCQ

A $100$ mark examination was administered to a class of $50$ students. Despite only integer marks being given, the average score of the class was $47.5$. Then, the maximum number of students who could get marks more than the class average is

A
$25$
B
$35$
C
$45$
✓
$49$

✓

Answer

Correct option: D.

$49$

d
(d)

Total number of students $=50$

Average marks of student $=47.5$

$\therefore$ Total marks of students

$=50 \times 47.5=2375$

Now, the student get integer marks Hence, the maximum number of students we will divide total mark by $48$.

$\frac{2375}{48}=49$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Which set is the subset of all given sets

The distance between the chords of contact of tangents to the circle ; $x^2+ y^2 + 2gx+2fy+ c=0$ from the origin $\&$ the point $(g , f)$ is :

If $\alpha $, $\beta $ and $\gamma $ are three consecutive terms of a non-constant $G.P.$ such that the equations $\alpha x^2 + 2\beta x + \gamma = 0$ and $x^2 + x -1 = 0$ have a common root, then $\alpha(\beta + \gamma )$ is equal to

Let $S=2+\frac{6}{7}+\frac{12}{7^{2}}+\frac{20}{7^{3}}+\frac{30}{7^{4}}+\ldots . .$ then $4 S$ is equal to

Let $g(x)$ be the inverse of the function $f(x)$ and $f'(x) = {1 \over {1 + {x^3}}}$. Then $g'(x)$ is equal to

Let $b$ be an non-zero real number. Suppose the quadratic equation $2 x^2+b x+\frac{1}{b}=0$ has two distinct real roots. Then

The equation of three circles are ${x^2} + {y^2} - 12x - 16y + 64 = 0,$ $3{x^2} + 3{y^2} - 36x + 81 = 0$ and ${x^2} + {y^2} - 16x + 81 = 0.$ The co-ordinates of the point from which the length of tangent drawn to each of the three circle is equal is

The sum of the series $\frac{1}{{1 + {1^2} + {1^4}}} + \frac{2}{{1 + {2^2} + {2^4}}} + \frac{3}{{1 + {3^2} + {3^4}}} + .........$ to $n$ terms is

A stair-case of length $l$ rests against a vertical wall and a floor of a room. Let $P$ be a point on the stair-case, nearer to its end on the wall, that divides its length in the ratio $1 : 2$. If the staircase begins to slide on the floor, then the locus of $P$ is

Let $S=\{(a, b): a, b, \in Z, 0 \leq a, b \leq 18\}$. The number of elements $(x, y)$ in $S$ such that $3 x+4 y+5$ is divisible by $19$ , is