A 100 mark examination was administered to a class of 50 students… - Vidyadip

MCQ

A $100$ mark examination was administered to a class of $50$ students. Despite only integer marks being given, the average score of the class was $47.5$. Then, the maximum number of students who could get marks more than the class average is

A
$25$
B
$35$
C
$45$
✓
$49$

✓

Answer

Correct option: D.

$49$

d
(d)

Total number of students $=50$

Average marks of student $=47.5$

$\therefore$ Total marks of students

$=50 \times 47.5=2375$

Now, the student get integer marks Hence, the maximum number of students we will divide total mark by $48$.

$\frac{2375}{48}=49$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 11 - 13. statistics→STD 11 - 13. statistics — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

A car driver knows four different routes from Delhi to Amritsar. From Amritsar to Pathankot, he knows three different routes and from Pathankot to Jammu he knows two different routes. How many routes does he know from Delhi to Jammu?

In a triangle $ABC,$ side $AB$ has the equation $2 x + 3 y = 29$ and the side $AC$ has the equation , $x + 2 y = 16$ . If the mid - point of $BC$ is $(5, 6)$ then the equation of $BC$ is :

All the vertices of a rectangle are of the form $(a, b)$ with $a, b$ integers satisfying the equation $(a-8)^2-(b-7)^2=5$. Then, the perimeter of the rectangle is

$8, 24, 48, 80, 120, .....:$

If in an infinite $G.P.$ first term is equal to the twice of the sum of the remaining terms, then its common ratio is

If $Arg(z)$ denotes principal argument of a complex number $z$, then the value of expression $Arg\left( { - i{e^{i\frac{\pi }{9}}}.{z^2}} \right) + 2Arg\left( {2i{e^{-i\frac{\pi }{{18}}}}.\overline z } \right)$ is

If for $x, y \in {R}, x>0,$

$y=\log _{10} x+\log _{10} x^{1 / 3}+\log _{10} x^{1 / 9}+\ldots . .$ upto $\infty$ terms and $\frac{2+4+6+\ldots+2 \mathrm{y}}{3+6+9+\ldots+3 \mathrm{y}}=\frac{4}{\log _{10} \mathrm{x}}$, then the ordered pair $(x, y)$ is equal to :

Three digit numbers are formed using the digits 0, 2, 4, 6, 8. A number is chosen at random out of these numbers. What is the probability that this number has the same digits?

The values of $a$ for which $2{x^2} - 2\,(2a + 1)\,\,x + a(a + 1) = 0$ may have one root less than $ a$ and other root greater than $a$ are given by

The tangent of angle between the lines whose intercepts on the axes are $a, -b$ and $b, -a$ respectively, is: