A 100, watt bulb working on 200 ,volt and a 200, watt bulb working on 100, volt have

Q: A $100\, watt$ bulb working on $200 \,volt$ and a $200\, watt$ bulb working on $100\, volt$ have

b (b) $R = \frac{{{V^2}}}{P}$ $ \Rightarrow $ ${R_1} = \frac{{200 \times 200}}{{100}} = 400\,\Omega $ and ${R_2} = \frac{{100 \times 100}}{{200}} = 50\,\Omega .$ Maximum current rating $i = \frac{P}{V}$ So ${i_1} = \frac{{100}}{{200}}$ and ${i_2} = \frac{{200}}{{100}}$$ \Rightarrow $ $\frac{{{i_1}}}{{{i_2}}} = \frac{1}{4}$.

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A $100\, watt$ bulb working on $200 \,volt$ and a $200\, watt$ bulb working on $100\, volt$ have

AResistances in the ratio of $4 : 1$
BMaximum current ratings in the ratio of $1:4$
CResistances in the ratio of $2 : 1$
DMaximum current ratings in the ratio of $1 : 2$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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