A $1.00 \times {10^{ - 20}}kg$ particle is vibrating with simple harmonic motion with a period of $1.00 \times {10^{ - 5}}sec$ and a maximum speed of $1.00 \times {10^3}m/s$. The maximum displacement of the particle is
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(a) ${v_{\max }} = a\omega = a \times \frac{{2\pi }}{T}$
==> $a = \frac{{{v_{\max }} \times T}}{{2\pi }}$
$A = \frac{{1.00 \times {{10}^3} \times (1 \times {{10}^{ - 5}})}}{{2\pi }} = 1.59\,mm$
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