MCQ
A $20\, ml$ sample of a $0.1\, M$ solution of the weak monoprotic acid $HA$ is titrated with $0.25\, M \,NaOH$, volume of $NaOH$ solution required till equivalent point is :- ............. $\mathrm{mL}$
- A$10$
- B$6$
- C$12$
- ✓$8$
✓
Answer
Correct option: D.
$8$
d
mili gram equivalent of ${HA}$ = mili gram equivalent of ${NaOH}$
mili gram equivalent of ${HA}$ = mili gram equivalent of ${NaOH}$
$0.1 \,\mathrm{N} \times 20\, \mathrm{mL}=0.25\, \mathrm{N} \times \mathrm{V}$
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