MCQ
$A + 2B \to 3C$ for the chemical reaction
- A$ - \frac{{d[A]}}{{dt}} = - \frac{1}{2}\frac{{d[B]}}{{dt}} = - \frac{1}{3}\frac{{d[C]}}{{dt}}$
- ✓$ - \frac{{d[A]}}{{dt}} = - \frac{1}{2}\frac{{d[B]}}{{dt}} = \frac{1}{3}\frac{{d[C]}}{{dt}}$
- C$\frac{{d[A]}}{{dt}} = \frac{1}{2}\frac{{d[B]}}{{dt}} = \frac{1}{3}\frac{{d[C]}}{{dt}}$
- D$ - \frac{{d[A]}}{{dt}} = 2\frac{{d[B]}}{{dt}} = 3\frac{{d[C]}}{{dt}}$

