A $400\, pF$ capacitor is charged with a $100\, V$ battery. After disconnecting battery this capacitor is connected with another $400\, pF$ capacitor. Then find out energy loss.
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Heat loss $ = \frac{{{C_1}{C_2}}}{{2\left( {{C_1} + {C_2}} \right)}}{\left( {{V_1} - {V_2}} \right)^2}$
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