A $5$ metre long wire is fixed to the ceiling. A weight of $10\, kg$ is hung at the lower end and is $1$ metre above the floor. The wire was elongated by $1\, mm$. The energy stored in the wire due to stretching is ......... $ joule$
A$0$
B$0.05$
C$100$
D$500$
Medium
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B$0.05$
b (b) $W = \frac{1}{2} \times F \times l = \frac{1}{2}mgl$
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