A 6 ,kg bomb at rest explodes into three equal pieces P, Q and R.… - Vidyadip

MCQ

A $6 \,kg$ bomb at rest explodes into three equal pieces $P, Q$ and $R$. If $P$ flies with speed $30 \,m / s$ and $Q$ with speed $40 \,m / s$ making an angle $90^{\circ}$ with the direction of $P$. The angle between the direction of motion of $P$ and $R$ is about

A
$143^{\circ}$
✓
$127^{\circ}$
C
$120^{\circ}$
D
$150^{\circ}$

✓

Answer

Correct option: B.

$127^{\circ}$

b
(b)

$P_\rho=30(2)=60 \,kg ms ^{-1}$

$P_Q=40(2)=80 \,kg ms ^{-1}$

$\tan \theta=\frac{60}{80}=3 / 4$

$\theta=37^{\circ}$

So angle between $P$ and $R$ will be $90^{\circ}+37^{\circ}=127^{\circ}$

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