A $60\, watt$ bulb operates on $220\,V$ supply. The current flowing through the bulb is
A$11/3\, amp$
B$3/11\, amp$
C$3\, amp$
D$6\, amp$
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B$3/11\, amp$
b (b) $P = Vi \Rightarrow i = \frac{P}{V} = \frac{{60}}{{220}} = \frac{3}{{11}}amp$
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